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Papa Charles poses an arithmetic problem for Canton's high school students. Did any of the parents try it as well?
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A LIVE PROBLEM
For the Pupils of the Canton High School to Solve.
In June, 1880, the population of Canton was 12,258; ten years later it was 26,189; now, December, 1892, two and a half years later, the city is taking a special census. Supposing the rate of increase for these two and a half years to be the same as the average rate of increase for the ten years ending June, 1890, what is the population of Canton now? Publish the solution in the NEWS DEMOCRAT Friday evening, giving the answer to the nearest integer.
C. F. STOKEY,
One of the Enumerators.
For the Pupils of the Canton High School to Solve.
In June, 1880, the population of Canton was 12,258; ten years later it was 26,189; now, December, 1892, two and a half years later, the city is taking a special census. Supposing the rate of increase for these two and a half years to be the same as the average rate of increase for the ten years ending June, 1890, what is the population of Canton now? Publish the solution in the NEWS DEMOCRAT Friday evening, giving the answer to the nearest integer.
C. F. STOKEY,
One of the Enumerators.
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1.
This is one of a series of documents that I have uploaded featuring Papa Charles in his role as a teacher and school administrator. You can find the whole list in:
2.
I like this item because it shows Papa Charles, once again, enjoying math problems. See also:
3.
Publish the solution in the NEWS DEMOCRAT Friday evening, giving the answer to the nearest integer.
So Papa Charles isn't going to make like King Solomon and offer to cut people up.
4.
C. F. STOKEY,
One of the Enumerators.
I don't know what "One of the Enumerators" means. Conceivably it's a joke, or a reference to a club of some sort.
5.
I hesitate to stick my neck out, but I think the answer is 33,630. If anybody else tries the problem, I'm sure they'll come up with a more correct answer.
This is one of a series of documents that I have uploaded featuring Papa Charles in his role as a teacher and school administrator. You can find the whole list in:
2.
I like this item because it shows Papa Charles, once again, enjoying math problems. See also:
3.
Publish the solution in the NEWS DEMOCRAT Friday evening, giving the answer to the nearest integer.
So Papa Charles isn't going to make like King Solomon and offer to cut people up.
4.
C. F. STOKEY,
One of the Enumerators.
I don't know what "One of the Enumerators" means. Conceivably it's a joke, or a reference to a club of some sort.
5.
I hesitate to stick my neck out, but I think the answer is 33,630. If anybody else tries the problem, I'm sure they'll come up with a more correct answer.
- 1880 population: 12258
- 1890 population: 26189
- Difference between 1890 and 1880: 13931
- 10 year Rate of increase: Difference divided by 1880 population: 1.136482297
- 1880 population plus 10 year rates times 1880 population makes 1890 population: 26189
- 2 1/2 year rate of increase: 10 year rate divided by 4: 0.2841205743
- So 1892 population should be 1890 population plus 2 1/2 year rate times 1890 population: 33629.83372
- Rounding the nearest integer makes 33630.
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